Q9 of 53 Page 158

In ΔABC, m∠B = 90, AB = BC. Then AB: AC =


In ΔABC, applying Pythagoras Theorem, we get,


AC2 = AB2 + BC2


As AB = BC,


⇒ AC2 = 2AB2


⇒ AB:AC = 1:√2


∴ Option (c) is correct.

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