In ΔABC, if
then m ∠C = ……

Let us assume,
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⇒ AB = x, AC = 2x and BC = √3x
As we see that, AC2 = AB2 + BC2
So by converse of Pythagoras Theorem, ΔABC is right angled and right angle at B.
Let ∠C = θ,
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⇒ θ = 30°
∴ Option (b) is correct.
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