In Δ ABC, m∠A = 90,
is an altitude. So AB2 = ……

By Pythagoras Theorem in ΔABD,
AB2 = AD2 + BD2 ...... (1)
As we know that,
If an altitude is drawn to hypotenuse of a right angled triangle, then the length of altitude is the geometric mean of lengths of segments of hypotenuse formed by the altitude.
AD2 = BD.CD ...... (2)
From equation (1) and (2)
AB2 = BD.CD + BD2
⇒ AB2 = BD(CD + BD)
⇒ AB2 = BD.BC
∴ Option (a) is correct.
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