Q9 of 53 Page 158

In ΔABC, AB2 + AC2 = 50. The length of the median AD = 3. So, BC =


In Δ ABC, using the theorem of Apolloneous, we know that,


For AD to be the median, we have,


AB2 + AC2 = 2(AD2 + BD2)


⇒ 50 = 2(32 + BD2)


⇒ 50 = 2 (9 + BD2)


⇒ 25 = 9 + BD2


⇒ BD2 = 16


⇒ BD = 4


⇒ BC = 2BD = 8


∴ Option (c) is correct.

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