In figure 7.25, AC is the length of a pole standing vertical on the ground. The pole is bent at point B, so that the top of the pole touches the ground at a point 15 meters away from the base of the pole. If the length of the pole is 25, find the length of the upper part of the pole.
Let the length of upper part of pole be x,
The length of AB becomes 25 – x.
Applying Pythagoras theorem in ΔABC,
(AC’)2 = AB2 + (BC’)2
⇒ x2 = (25 – x)2 + 152
⇒ x2 = 625 + x2 – 50x + 225
⇒ 50x = 850
⇒ x = 17 m
∴ The length of the upper part of the pole is 17 meters.
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