m∠B = 90 in ΔABC.
is altitude to
.
If BM = 15, AC = 34, find AB.

Let AM = x, CM = 34 – x
BM2 = AM × MC
⇒ x2 – 34x = – 225
⇒ x2 – 34x + 225 = 0
⇒ x2 – 25x – 9x + 225 = 0
⇒ x(x – 25) – 9(x – 25) = 0
⇒ (x – 9)(x – 25) = 0
⇒ x = 9, 25
AB2 = 152 + 92
⇒ AB2 = 306
AB = √306 units
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