Q9 of 53 Page 158

In ΔABC, AB = BC = . m∠B


Let us assume,



⇒ AB = BC = x and AC = √2x


As we see that, AC2 = AB2 + BC2


So by converse of Pythagoras Theorem, ΔABC is right angled and right angle at B.


∴ Option (c) is correct.

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