In ΔPQR m∠Q = 90, PQ = x, QR = y and
. D
. Find PD, QD, RD in terms of x and y.
m
Q = 90
Applying Pythagoras theorem
PR = √(x2 + y2)
PQ2 = PD × PR
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QR2 = RD × PR
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QD2 = PD × RD
⇒ QD2![]()
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