Q1 of 39 Page 91

The sum of the squares of three consecutive positive integers is 50. Find the integers.

Let the first integer be x

other consecutive integers will be x + 1, x – 1.


According to the question,


(x)2 + (x + 1)2 + (x – 1)2 = 50


⇒ x2 + x2 + 1 + 2x + x2 + 1 – 2x = 50


⇒ 3x2 + 2 = 50


⇒ 3x2 = 48


⇒ x2 = 16


⇒ x = ±4


So, the 3 integers can be either 3, 4,5 or – 3, – 4, – 5.


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