Q29 of 39 Page 91

Form a quadratic polynomial whose one of the zeroes is – 15 and sum of the zeroes is 42.

Given one of the zeroes(a) = – 15


Sum of zeroes = a + b = 42


⇒ b = 42 + 15


⇒ b = 57


So, Quadratic equation = x2 – (a + b)x + ab


⇒ x2 – 42x + (15×57)


⇒ x2 – 42x + 855


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