Find the value of k for which one root of the quadratic equation kx2 – 14x + 8 = 0 is six times the other.
Let one of the root be ‘a’
So another root = 6a
As, the sum of roots = ![]()
⇒ 7a = 14/k
⇒ a = 2/k ...... (i)
Also, ![]()
⇒ 6a2 = 8/k
putting the value of a from (i)
![]()
⇒ 3k = k2
⇒ k(k – 3) = 0
⇒ k = 0 or k = 3
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