Solve for x:
; x ≠ 0, –1, 2.
Given, ![]()
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⇒ 35x2 – 25x = 23(2x2 – 2x – 4)
⇒ 35x2 – 25x = 46x2 – 46x – 92
⇒ 11x2 – 21x – 92 = 0
⇒ 11x2 – 44x – 23x – 92 = 0
⇒ 11x(x – 4) – 23(x – 4) = 0
⇒ (11x – 23)(x – 4) = 0
⇒ x = 23/11 or x = 4
Couldn't generate an explanation.
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