Find the inverse of each of the following matrices:

Now, |A| = cos
(cos
) + sin
(sin
)
= 1
Hence, A – 1 exists.
Cofactors of A are
C11 = ![]()
C12 = ![]()
C21 = ![]()
C22 = ![]()
Since, adj A = ![]()
(adj A) = ![]()
= ![]()
Now, A – 1 =
.adj A
A – 1 =
.![]()
A – 1 = ![]()
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