Find the matrix X satisfying the matrix equation:
.
Let A =
B = ![]()
So, AX = B
Or, X = A – 1B
|A| = – 7
Cofactors of A are
C11 = – 2 C12 = 1
C21 = – 3 C22 = 5
Since, adj A = ![]()
(adj A) = ![]()
= ![]()
Now, A – 1 = ![]()
A – 1 = ![]()
So, X = ![]()
Hence, X = ![]()
X = ![]()
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