Show that
satisfies the equation A2 + 4A – 42I = O. Hence, find A – 1.
A = ![]()
A2 =
= ![]()
= ![]()
4A = 4 ![]()
42I = 42![]()
Now,
A2 + 4A – 42I = ![]()
= ![]()
Hence, = ![]()
Now, A2 + 4A – 42I = 0
= A – 1. A . A + 4 A – 1.A – 42 A – 1.I = 0
= IA + 4I – 42A – 1 = 0
= 42A – 1 = A + 4I
= A – 1 = ![]()
= 
A – 1 = 
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