Find the inverse of each of the following matrices.

|A| =
– 0 + 0
= (
)
= – 1
Hence, A – 1 exists
Cofactors of A are:
C11 = – 1 C21 = 0 C31 = 0
C12 = 0 C22 =
C32 = ![]()
C13 = 0 C23 =
C33 = ![]()
adj A = 
= 
So, adj A = 
Now, A – 1 =
.adj A
So, A – 1 =
.
Hence, A – 1 = 
Couldn't generate an explanation.
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