Q13 of 74 Page 7

If , then show that A – 3I = 2 (I + 3A – 1).

A =


|A| = 4 – 10 = – 6 adj A =


A – 1 =


To Show: A – 3I = 2 (I + 3A – 1)


LHS A – 3I =


=


R.H.S 2 (I + 3A – 1) = 2I + 6A – 1 =


=


=


Hence, A – 3I = 2 (I + 3A – 1)


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