For the following pairs of matrices verify that (AB)–1 = B – 1A – 1:

|A| = 1
Adj A = ![]()
A – 1 = ![]()
B = ![]()
|B| = – 1
B – 1 = ![]()
Also, AB = ![]()
= ![]()
|AB| = 407 – 406 = 1
And, adj(AB) = ![]()
(AB) – 1 = ![]()
= ![]()
Now, B – 1A – 1 = ![]()
= ![]()
Hence, (AB) – 1 = B – 1A – 1
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