Let
. Find (AB) – 1.
A = ![]()
|A| = 15 – 14 = 1
adj A = ![]()
A – 1 = ![]()
B = ![]()
|B| = 54 – 56 = – 2 adj B = ![]()
B – 1 = ![]()
Now, (AB) – 1 = B – 1A – 1
= ![]()
= ![]()
= ![]()
(AB) – 1 = 
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