Find the inverse of each of the following matrices:
Now, |A| = – 1
0
Hence, A – 1 exists.
Cofactors of A are
C11 = 
C12 = – 1
C21 = – 1
C22 = 0
Since, adj A = 
(adj A) = 
= 
Now, A – 1 = 
.adj A
A – 1 = 
.
A – 1 = 
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