Find the matrix X satisfying the equation:
.
Let A =
B =
C = ![]()
Then The given equations becomes as
AXB = I
= X = A – 1B – 1
|A| = 6 – 5 = 1
|B| = 10 – 9 = 1
A – 1 = ![]()
B – 1 = ![]()
= X = A – 1B – 1 = ![]()
= ![]()
= ![]()
Hence, X = ![]()
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