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7. Adjoint and Inverse of a Matrix
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Q12 of 74 Page 7

Given , compute A – 1 and show that 2A – 1 = 9I – A.

A =


|A| = 14 – 12 = 2 adj A =


A – 1 =


To Show: 2A – 1 = 9I – A


L.H.S 2A – 1 = 2.


R.H.S 9I – A =


=


Hence, 2A – 1 = 9I – A


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Questions · 74
7. Adjoint and Inverse of a Matrix
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