Given
, compute A – 1 and show that 2A – 1 = 9I – A.
A = ![]()
|A| = 14 – 12 = 2 adj A = ![]()
A – 1 = ![]()
To Show: 2A – 1 = 9I – A
L.H.S 2A – 1 = 2.![]()
R.H.S 9I – A = ![]()
= ![]()
Hence, 2A – 1 = 9I – A
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