If
. Verify that A3 – 6A2 + 9A – 4I = O and hence fid A – 1.
A = 
A3 = A2.A
A2 = 
= 
A2.A = 
= 
= 
Now, A3 – 6A2 + 9A – 4I

= 
= 
Thus, A3 – 6A2 + 9A – 4I
Now, (AAA) A – 1. – 6(A.A) A – 1 + 9.A A – 1 – 4I.A – 1 = 0
A2 – 6A + 9I = 4A – 1
= A – 1 = ![]()
Now,

= 
= 
= 
Hence, A – 1 = 
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