Using properties of determinants prove that:
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[R1’ = R1 + R2]
[R1’ = R1/(a + b)]
[R2’ = R2 + R3]

[R2’ = R1/(b + c)]
[R1’ = R1 + R2]
= (a + b)(b + c){0 + 2( - b + a + b + c) + 0} [expansion by first row]
= 2(a + b)(b + c)(c + a)
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