Q27 of 110 Page 270

Mark the tick against the correct answer in the following:

The solution set of the equation is


To find: Value of x


We have,


Applying


⇒


Applying


⇒


Expanding along R1


⇒ (3x-11){(3x-11)(3x-8) – (3)(11-3x)} – (11-3x){(0)((3x-8) – (11-3x)(3)} = 0


⇒ (3x-11){(3x-11)(3x-8+3)} – (11-3x){–(11-3x)(3)} = 0


⇒ (3x-11)2(3x-5)} + (3x-11){(3x-11)(3)} = 0


⇒ (3x-11)2(3x-5)} + (3x-11)2(3)} = 0


⇒ (3x-11)2(3x-5+3) = 0


⇒ (3x-11)2(3x-2) = 0


⇒

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