Q23 of 110 Page 270

Mark the tick against the correct answer in the following:

If then x = ?


To find: Value of x


We have,


Applying


⇒


Applying


⇒


Expanding along R1


⇒ [1{(x)(-2) – (6)(2)}] = 0


⇒ [1{-2x – 12}] = 0


⇒ -2x-12 = 0


⇒ -2x = 12


⇒ x = -6

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