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6. Determinants
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Q22 of 110 Page 270

Mark the tick against the correct answer in the following:


To find: Value of


We have,


Applying


⇒


Applying


⇒


Expanding along R1


⇒ [2{(5)(x+14) – (6)(x+10)} – 3{(4)(x+14) – (6)(x+7)} + 4 {(4)(x+10) – (5)(x+7)}]


⇒ [2{5x + 70 – 6x – 60} – 3{4x + 56 -6x - 42} + 4 {4x + 40 – 5x - 35}]


⇒ [2{10 - x} – 3{14 -2x} + 4 {5 - x}]


⇒ [20 – 2x – 42 + 6x + 20 - 4x]


⇒ -2

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20

Mark the tick against the correct answer in the following:


21

Mark the tick against the correct answer in the following:


23

Mark the tick against the correct answer in the following:

If then x = ?


24

Mark the tick against the correct answer in the following:

The solution set of the equation is


Questions · 110
6. Determinants
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