Q4 of 110 Page 270

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To find: Value of


Formula used: i2 = -1


We have,


On expanding the above,


⇒ (a + ib) (a – ib) – (-c + id) (c + id)


⇒ (a2 – iab + iba – i2b2) - (-c2 – icd + icd + i2d2)


⇒ {a2 – iab + iba – (-1)b2} – {-c2 – icd + icd + (-1)d2}


⇒ {a2 – iab + iba + 1b2} – {-c2 – icd + icd - 1d2}


⇒ a2 + b2 + c2 + d2

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