Q25 of 110 Page 270

Mark the tick against the correct answer in the following:

The solution set of the equation is


To find: Value of x


We have,


Applying


⇒


Applying


⇒


Expanding along R1


⇒ [x-2{(-1)(-40) – (-4)(-11)} -1 {(x-4)(-40) – (-4)(x-8)} + 2 {(x-4)(-11) – (-1)(x-8)] = 0


⇒ [(x-2){40-44} -1 {(-40x + 160 + 4x – 32} + 2 {-11x + 44 + x - 8}] = 0


⇒ [(x-2){-4} -1 {(- 36x + 128} + 2 {-10x+36}] = 0


⇒ [-4x + 8 + 36x - 128 - 20x + 72] = 0


⇒ 12x – 48 = 0


⇒ x = 4

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