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6. Determinants
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Q15 of 110 Page 270

Mark the tick against the correct answer in the following:


To find: Value of


We have,


Applying


⇒


Applying


⇒


Expanding along C3


⇒ [1{(a2-1)(a-1) – (a-1)(2a – 2)}]


⇒ [1{(a-1)(a+1)(a-1) – (a-1)2(a – 1)}]


⇒ [{(a+1)(a-1)2 – 2(a-1)2}]


⇒ [{(a-1)2 (a+1-2)}]


⇒ [{(a-1)2 (a-1)}]


⇒ (a-1)3

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Questions · 110
6. Determinants
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