Q8 of 110 Page 270

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To find: Value of


We have,


⇒


Taking 2 common from R2


⇒


Taking 6 common from R3


⇒


Applying


⇒


Applying


⇒


Expanding column 1


⇒ 12 [1{(1)(14)-(6)(2)}]


⇒ 12 [1{(14)-(12)}]


⇒ 12[2]


⇒ 24

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