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6. Determinants
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Q19 of 110 Page 270

Mark the tick against the correct answer in the following:


To find: Value of


We have,


Applying


⇒


⇒


Taking (b – a) common


⇒


Applying


⇒


⇒


Taking (c - b) common


⇒


Expanding along C3


⇒ (b – a) (c – b) [1{(c) (1) – (a) (1)}]


⇒ (b – a) (c – b) (c – a)


⇒ (a – b) (b – c) (c – a)

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Mark the tick against the correct answer in the following:


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Questions · 110
6. Determinants
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