Q12 of 110 Page 270

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To find: Value of


Formula Used: sin(A+B) = sinAcosB+cosAsinB


We have,


Applying


⇒


Applying


⇒


We know, sin(A+B) = sinAcosB+cosAsinB


⇒


Applying


⇒


⇒


= 0


When two columns are identical then the value of determinant is 0

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