Q4 of 110 Page 269

Find the value of k for which the
points P(5, 5), Q(k, 1) and R(11, 7) are collinear.


Since they are collinear, the area will be 0


→


Expanding with C3


→ 0 = (7k-11)-(35-55)+(5-5k)


→ 0= 2k-14


→ 2k=14


∴ k=7


More from this chapter

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2

Use determinants to show that the following points are collinear.

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 3

Find the value of k for which the
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 5

Find the value of k for which the
points A(1, -1), B(2, k) and C(4, 5) are collinear.

 6

Find the value of k for which the area of aABC having vertices A(2, -6), B(5, 4) and C(k, 4) is 35 sq units.