Mark the tick against the correct answer in the following:

To find: Value of

We have,

Applying +

⇒

⇒

⇒ (a+b+c)

Expanding along R₁

⇒ (a+b+c)[2{(c) (c) – (b) (a)} -1{(c+a)(c)-(a+b)(a)} + 1{(c+a)(b)-(a+b)(c)}]

⇒ (a+b+c)[2{c² – ab} -1{c²+ac-a²-ab} + 1{bc+ba-ac-bc}]

⇒ (a+b+c)[2c² – 2ab - c² – ac + a² + ab + ba - ac]

⇒ (a+b+c)[c² + a² - 2ac]

⇒ (a+b+c)(c – a)²