Three rods of lengths 20 cm each and area of cross-section 1 cm2 are joined to form a triangle ABC. The conductivities of the rods are KAB = 50 J s–1 m–1 °C–1, KBC = 200 J s–1 m–1 °C–1 and KAC = 400 J s–1 m–1 °C–1. The junctions A, B and C are maintained at 40°C, 80°C and 80°C respectively. Find the rate of heat flowing through the rods AB, AC and BC.
Given:
Length of all the rods: x= AB=BC=AC = 20 cm = 0.2 m
Area of cross section of these rods: A = 1 cm2 = 0.0001 m2.
Thermal conductivity of rod AB : KAB = 50 J s–1 m–1 °C–1
Thermal conductivity of rod BC : KBC = 200 J s–1 m–1 °C–1
Thermal conductivity of rod AC : KAC = 400 J s–1 m–1 °C–1
Temperature at A : T1 = 40 °C
Temperature at B : T2 = 80 °C
Temperature at C : T3 = 80 °C
Formula used:
Rate of amount of heat flowing or heat current is given as:![]()
Here, Δθ is the amount of heat transferred, ΔT is the temperature difference, K is the thermal conductivity of the material, A is the area of cross section of the material and x is the thickness or length of the material.
(1)
Rate of heat flowing in the rod AB is![]()
![]()
![]()
Hence, rate of heat flowing through the rod Ab is 1 J/s or 1 W
(2)
Rate of heat flowing in the rod BC is![]()
![]()
![]()
Hence, the rate of heat flowing through the rod BC is 0 as both the ends of the rods are maintained at same temperature.
(3)
Rate of heat flowing in the rod BC is![]()
![]()
![]()
Hence, the rate of heat flowing through the rod AC is 8 J/s.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.