A hollow metallic sphere of radius 20 cm surrounds a concentric metallic sphere of radius 5 cm. The space between the two spheres in filled with a nonmetallic material. The inner and outer spheres are maintained at 50°C and 10°C respectively and it is found that 100 J of heat passes from the inner sphere to the outer sphere per second. Find the thermal conductivity of the material between the spheres.
Let’s redraw the circuit –

Let-
Radius of the inner sphere =a
Radius of the outer sphere = b
Given –
a = r1 = 5cm = 0.05m
b = r2 = 20cm = 0.2m
θ1 = T1 = 50°C
θ2 = T2 = 10°
Consider an imaginary shell of radii r and thickness dr.
Area, ![]()
Now, rate of flow of heat –
=- ![]()
= is change in temperature.
A= Area of cross section of the tube
K = thermal conductivity of the tube
dr = change in length
Here, the negative sign is for decrease in temperature with increase in radius.
q = - ![]()
Taking integral on both sides –
=![]()
Solving above integral –
q=
= k(
) = 100 (given)
Substituting the values,
K =
= 2.8 = 3 W m-1°C-1
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