Determine whether the given value of xĂÂ is a solution of the given equationor not: x 2+ x + 1 = 0; x = -1.
x 2 + x + 1 = 0
Let x = -1
⇒ (-1) 2 + (-1) + 1
= 1 – 1 + 1
= 1.
Therefore, the given value of x is not a solution of the given equation.
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