Determine whether the given quadratic equation has root(s). If so, findthe root(s). y 2– 6y+2=0.
a = 1, b = –6 and c = 2
Δ = b 2 – 4ac
= (–6) 2 – 4(1)(2)
= 36 – 8
= 28
Therefore the quadratic equation has real roots.
α=3-√7
β=3 + √7
Therefore the roots are 3 + √7 and 3 – √7.
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