Determine the nature of roots of the quadratic equation x 2â 6x+ 9 = 0.
In this equation x 2 – 6x + 9 = 0
a = 1, b = -6 and c = 9 as per the equation given above.
Putting the values of a, b and c in the equation b 2 – 4ac
b 2 – 4ac = (-6) 2 – 4(1)(9)
= 36 – 36
= 0
Since b 2 – 4ac = 0,
The equation has two real and equal roots.
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