Determine value(s) of p for which the given quadratic equation 5px 2-8x + 2 = 0 has real roots:
a = 5p,
b = -8 and
c = 2
Δ = b 2 – 4ac
= (-8) 2 – 4(5p)(2)
= 64 – 40p
Δ ≥ 0
Therefore 64 – 40p ≥ 0
64 ≥ 40p
∴
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