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4. Quadratic Equations
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Q15 of 134 Page 4


Determine whether the given values of x are solutions of the givenequation or not:
x 2+ 6x + 5 = 0; x = -1, x = -5.


x 2 + 6x + 5 = 0
Put x = -1
⇒ (-1) 2 + 6(-1) + 5

= 1 – 6 + 5

= 0
Put x = -5
⇒ (-5) 2 + 6(-5) + 5

= 25 - 30 + 5

= 0
Therefore the given value of x is a solution of the given equation.

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Questions · 134
4. Quadratic Equations
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