Determine whether the given quadratic equation has root(s). If so, findthe root(s): 3y ²+ (6 + 4a)y + 8a = 0.

b = (6 + 4a) and

c = 8a
Δ = b ² – 4ac

= (6 + 4a) ² – 4(3)(8a)

= 36 + 16a ² + 48a – 96a
= 16a ² - 48a + 36

= (4a – 6) ²
Therefore the quadratic equation has real roots.

= -2
Therefore, the roots are - and –2.