Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse.
36x2 + 4y2 = 144.
Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse.
36x2 + 4y2 = 144.
36x2 + 4y2 = 144.
The given equation of the ellipse can be written in standard form as.
= 1 or
= 1
since the denominator of x2 < denominator of y2, the major axis is along the y-axis. Comparing the given equation with the standard equation
= 1
we have b = 2 and a = 6
Also, c =
=
=
= 4
and e =
=
=
= ![]()
Hence the foci, (0, c) and (0, c) are (0, 4
) and (0, -4
). Vertices, (0, a) and (0, a) are (0,6) and (0,-6); the length of the major axis, 2a is 12 units; the length of the minor axis, 2b is 4 units and the eccentricity of the ellipse, e is
.
The length of latus rectum,
is
=
units.
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