Q5 of 62 Page 11

Find the equation of the circle with centre (–a, –b) and radius .


Here, h = -a, k = -b and r = . Therefore, the required equation of the circle is

(x – (-a))2 + (y – (-b))2 = (

(x + a)2 + (y + b)2 = a2 – b2

or x2 + 2ax + a2 + y2 + 2by + b2 = a2 – b2

or x2 + y2 + 2ax+ 2by + 2b2 = 0.

More from this chapter

All 62 →