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11. Conic Sections
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Q25 of 62 Page 11

Find the equation of the parabola that satisfies the given conditions: Vertex (0,0); focus (–2,0)


Since the vertex is at (0,0) and the focus is at (- 2, 0) which lies on x-axis, the x-axis is the axis of the parabola. Therefore, equation of the parabola is of the form

y2 = - 4ax ⇒ y2 = - 4(2)x = - 8x

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Find the equation of the parabola that satisfies the given conditions: Vertex (0,0) passing through (2,3) and axis is along x-axis.

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Questions · 62
11. Conic Sections
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