Find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum. x2 = 6y
Find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum. x2 = 6y
The given equation involves x2, so the axis symmetry is along y-axis.

The coefficient of y is positive so that parabola opens upward. Comparing with the given equation x2 = 4ay, we find that a =
Thus, the focus of the parabola is
and the equation of the directrix of the parabola is y = ![]()
Length of the latus rectum LL' is 4a = 4 ×
= 6.
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