Q54 of 62 Page 11

Vertices (± 2, 0), foci (± 3, 0)


Since the foci are on x-axis, the equation of the hyperbola is of the form

= 1

Given : vertices are (± 2, 0), a = 2

Also, since foci are (± 3, 0), c = 3 and b2 = c2 – a2 = 9 – 4 = 5

Therefore, the equation of the hyperbola is

= 1.

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5y2 – 9y2 = 36.

53
49y2 – 16x2 = 784.

55
Vertices (0, ± 5), foci (0, ± 8)

56
Vertices (0, ± 3), foci (0, ± 5)