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Q61 of 62 Page 11

Vertices(± 7, 0), e =

Here a = 7 and e =

But e = ⇒ = or c =

Also, c² = a² + b² ⇒ = 49 + b²

or = b²

or = b²

or = b² or = b²

or b² =

Therefore, the equation of the required hyperbola

= 1 or = 1

or = 1 or 7x² – 9y² = 343.

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