Vertices (0, ± 3), foci (0, ± 5)
Vertices (0, ± 3), foci (0, ± 5)
Since the foci are on y-axis the equation of the hyperbola is of the form
= 1
Given: vertices are (0, ± 3), a = 3
Also, since foci are(0, ± 5), c = 5 and b2 = c2 – a2 = 25 – 9 = 16
Therefore, the equation of the hyperbola is
= 1.
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